Facts about Seymour, Wisconsin
Seymour is a city in Outagamie County, Wisconsin, United States. The population was 3,451 at the 2010 census. The city is located within the Town of Seymour and the Town of Osborn.
Seymour is located at 44°30′30″N 88°19′42″W (44.508499, -88.3284). According to the United States Census Bureau, the city has a total area of 2.67 square miles (6.92 km²), all of it land.
As of the census of 2010, there were 3,451 people, 1,458 households, and 915 families residing in the city. The population density was 1,292.5 inhabitants per square mile (499.0/km²). There were 1,565 housing units at an average density of 586.1 per square mile (226.3/km²). The racial makeup of the city was 94.3% White, 0.3% African American, 2.6% Native American, 0.2% Asian, 0.7% from other races, and 1.8% from two or more races. Hispanic or Latino of any race were 2.0% of the population.
Serving Seymour, Wisconsin
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